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“执行定理”的证明(c+)

时间:2019-09-11 10:41 作者:未知
 

 

 

This is an in-mail fromTYUST. 新入の者--What is going on ?(redirected)new 本期开始分组发送邮件,搭载数学类学院等链接。今日学院:暂无。||新闻+||....Perfectoid....[路过]
阶段温习...(接前:030201)“执行定理” 的证明(c+)..“逻辑对接” 的补充 (c+) ~ (f+)..第二段第13句.补充.12B13| | |para2.13| | |18 19 20.注: 用 X, B, H 替换 X, B, A.12,B,13:X, B, H.18~20: X, B, A..评论: 做这个补充是为了对接第三段..*第三段温习及逻辑模块..Let C = 1/2 A.. 20 | para3.1 | 21.注: 减半器.21: C..Then we have lct(X, B, |A|R) = 1/2 lct(X, B, |C|R), hence it is enough to give a positive lower bound for lct(X, B, |C|R).. 21 | para3.2 | |22 23.注: A半减后 lct 加倍.22: lct 加倍式.23: 求lct(X, B, |C|R)的正下界..Let n, m, eps be the numbers given by Proposition 5.9 for the data d, r, eps..d r eps | para3.3 | n m eps.注: 此处的输出是待定量..Pick L∈|C|R.. 21 | para3.4 | 24.注: 单句构造L.24: L..Let s be the largest number such that (X, B + sL) is eps-lc..18 19 24eps| | | | para3.5 | 25.注: 引入s 并与 eps 联立.25: 最大的s, 使(X, B + sL) eps-lc..评论: 此句是第三段的核心..It is enough to give a positive lower bound for s.. 25 | para3.6 | 26.注: 问题转移到s上.26: 求 s 的正下界..In particular, we can assume s≤1.. 26 | para3.7 | 27.注: 给s加了上界约束.27: 假定 s 不超过 1..评论: 第三段的轴心是 (X, B + sL) eps-lc..小结: A减半, 最大s, eps-lc(简记: s~eps-lc).
符号大全上下标.|| 常用:↑↓ πΓΔΛΘΩμφΣ∈∪ ∩ ≤ ≥ ≠≡ .Leonhard EulerCarl Friedrich GaussGrothendieckGlossary(AG)*第一轮读写链接Abstract8/4IntroductionBoundedness of singular Fano varieties (1)8/5Boundedness of singular Fano varieties (2)8/6Boundedness ofsingularFano varieties (3)8/7Boundedness ofsingularFano varieties (4)8/8Boundedness ofsingularFanovarieties (5)8/9Boundedness ofsingularFanovarieties(6)8/9Jordan property of Cremona groups8/10Lc thresholds of lR-linear systems 8/11Lc thresholds of anti-log canonical systems of Fano pairs (1)8/12Lc thresholds of anti-log canonical systems of Fano pairs (2) 8/13Lc thresholds of R-linear systems with bounded degree 8/14Complements near a divisor8/15.........Proposition 5.211/9...Proposition 5.5. 11/5